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-9p^2+12p+1=5
We move all terms to the left:
-9p^2+12p+1-(5)=0
We add all the numbers together, and all the variables
-9p^2+12p-4=0
a = -9; b = 12; c = -4;
Δ = b2-4ac
Δ = 122-4·(-9)·(-4)
Δ = 0
Delta is equal to zero, so there is only one solution to the equation
Stosujemy wzór:$p=\frac{-b}{2a}=\frac{-12}{-18}=2/3$
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